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MEMMOVE

Section: Linux Programmer's Manual (3)
Updated: 1993-04-10
Index Return to Main Contents

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NAME

memmove - copy memory area  

SYNOPSIS

#include <string.h>

void *memmove(void *dest, const void *src, size_t n);

 

DESCRIPTION

The memmove() function copies n bytes from memory area src to memory area dest. The memory areas may overlap: copying takes place as though the bytes in src are first copied into a temporary array that does not overlap src or dest, and the bytes are then copied from the temporary array to dest.  

RETURN VALUE

The memmove() function returns a pointer to dest.  

CONFORMING TO

SVr4, 4.3BSD, C89, C99, POSIX.1-2001.  

SEE ALSO

bcopy(3), memccpy(3), memcpy(3), strcpy(3), strncpy(3), wmemmove(3)  

COLOPHON

This page is part of release 3.35 of the Linux man-pages project. A description of the project, and information about reporting bugs, can be found at http://man7.org/linux/man-pages/.

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Index

NAME

SYNOPSIS

DESCRIPTION

RETURN VALUE

CONFORMING TO

SEE ALSO

COLOPHON

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